Consider two batteries, one 24.0 V and other 6V which are connected with two bul
ID: 1683811 • Letter: C
Question
Consider two batteries, one 24.0 V and other 6V which are connected with two bulbs in series but batteries are connected wrong, i.e. both negative terminals are connected. The resistance of the bulbs is 5.0 and 10.0 ohms. Sketch a neat diagram in each case and calculate the power consumed by each bulb if: A) Bulbs are connected in with the battery terminal in series B) Bulbs are connected with battery terminals in parallel Consider two batteries, one 24.0 V and other 6V which are connected with two bulbs in series but batteries are connected wrong, i.e. both negative terminals are connected. The resistance of the bulbs is 5.0 and 10.0 ohms. Sketch a neat diagram in each case and calculate the power consumed by each bulb if: A) Bulbs are connected in with the battery terminal in series B) Bulbs are connected with battery terminals in parallelExplanation / Answer
since batteries are connected wrongly, they oppose each other so resulting voltage is 24-6 instead of 24+6. (1) if connected in series, voltage is 18V and total resistance of circuit is 10+5 = 15ohms. thus, current = 18/15 through both bulbs. Power P = I^2R. you know current and you know resistances. find P. (2) if in parallel, voltage across both bulbs will be same which is 18V. Power is also given by formula V^2/R. you can easily find the power.