A 37.8-cm diameter disk rotates with a constant angular acceleration of 3.0 rad/
ID: 1685052 • Letter: A
Question
A 37.8-cm diameter disk rotates with a constant angular acceleration of 3.0 rad/s2. It starts from rest at t = 0, and a line drawn from the center of the disk to a point P on the rim of the disk makes an angle of 57.3° with the positive x-axis at this time.(a) Find the angular speed of the wheel at t = 2.30 s.
(b) Find the linear velocity and tangential acceleration of P at t = 2.30 s.
linear velocity
tangential acceleration
c) Find the position of P (in degrees, with respect to the positive x-axis) at t = 2.30s.
Explanation / Answer
diameter=37.8 cm radius r = 18.9 cm = 0.189 m, constantangular acceleration a = 3.00 rad/s2, initial angular velocity = 0, initial position of P= ?o = 57.3o = 1 rad At t = 2.30 s, a) the angularspeed of the wheel ? = at = 6.90 rad/s b) the linearvelocity of P: v = ?r = 1.3041 m/s tangentialacceleration of P: at = a * r = 0.567m/s2 c) ? = ?o +0.5at^2 = 8.935rad = 511.97 deg Finally It appears as 511.97 - 360 =151.97 deg