Pls help.. The legs of a weight lifter must ultimately support the weights he ha
ID: 1699306 • Letter: P
Question
Pls help..The legs of a weight lifter must ultimately support the weights he has lifted. A human tibia (shinbone) has a circular cross section of approximately 3.60 cm outer (R) diameter and 2.50 cm inner (r) diameter. (The hollow portion contains marrow.)
If a 90.0 kg lifter stands on both legs, what is the heaviest weight he can lift without breaking his legs, assuming that the breaking stress of the bone is 200 MPa?
w=??????? N
Total Force F = (90.0kg X 9.8)+F
= (882+F)
A= pi(R^2-r^2)
F= (stress*area) = (200MPa*5.27*10^-4) = 105400 or even if I remove the addtional (882)
it still says the answer is wrong...where did I go wrong?
Explanation / Answer
Txs I figured it out.