In procedure 2: suppose red light passes through a double slit and falls on a sc
ID: 1709434 • Letter: I
Question
In procedure 2: suppose red light passes through a double slit and falls on a screen. In the diffraction pattern, the distance from the central maximum to the first maximum is 5 mm.a) The distance from the first minimum (dark spot) to the second minimum in the diffraction pattern is
less than 5 mm
exactly 5 mm
more than 5 mm
b) Blue light has a higher frequency than red light. If you switch the light falling on the double slit from red to blue, the distance between the central and first maxima on the screen would
decrease
remain the same
increase
c) Diffraction experiments are usually done with diffraction gratings (which have many slits) instead of a double slit. The advantage of the diffraction grating is
all the maxima are brighter
there are many more maxima generated
less light goes to the central maximum, and more to the other maxima
it eliminates the central maximum
all the maxima are farther apart
all the maxima are closer together
d) For this question, there is more than one correct answer!
You can change L (the distance from the slits to the screen), d (the distance between the slits) and ? (the wavelength of the light used). Which combination would double the distance between the maxima?
halve d, double ?, double L
halve L, leave d and ? unchanged
double L, halve d, leave ? unchanged
double L, leave ? and d unchanged
double L, double d, leave ? unchanged
halve L, halve d, halve ?
double L, double ?, leave d unchanged
double ?, leave L and d unchanged
halve d, leave L and ? unchanged
halve d, double ?, leave L unchanged
double L, double ?, double d
double d, halve L, leave ? unchanged
Explanation / Answer
The distance from the first minimum (dark spot) to the second minimum in the diffraction pattern is exactly the same of the distance of the first bright to the central bright. Because the minimum intensity will be obtained at the regular intervals of the value m (0,1,2....) according to the equation
dsin = m