In procedure 2: suppose an inclined plane is 120 cm long, and is tipped at angle
ID: 2197150 • Letter: I
Question
In procedure 2: suppose an inclined plane is 120 cm long, and is tipped at angle?=13o. The 0 cm mark is at the bottom. (NOTE: In the lab, the 0 cm mark will be at the top.) Photogate 1 is at the28.5cm mark, and photogate 2 is at the59.1cm mark along the track, Assume
- The bottom of the track is at 0 J potential energy.
- The total mass of the cart is615g.
- The track is totally frictionless
NOTE: Be careful of units!
a) Find the potential energy of the cart .
- At photogate 1:J
- At photogate 2:J
b) Suppose the cart is released at rest at photogate 2 (the higher point on the track). Find the speed of the cart as it passes photogate 1.
m/s
Explanation / Answer
kenetic energy = ke = .5 * m *v^2 1.09 - 0.449 = .5 * 0.824 * v^2 0.641 = .412 * v^2 v^2 = 1.556 v = 1.247