Problem 1: What are the four (moisture) conditions or status for aggregates? (10
ID: 1712542 • Letter: P
Question
Problem 1: What are the four (moisture) conditions or status for aggregates? (10 Points) Problem 2: A sam ple of aggregate has moisture content of 10%. Its absorption capacity is 4%, what is the weight of moisture (or water content) in 100 lb of this sample? And what is the oven-dry weight of this aggregate sample? , and what is the weight of free water (or surface water) in this sample? (15 point) Problem 3: Fill the missing data in the sieve analysis test calculation (show calculation) 10 points) Sieve Size Sieve Weight Percent Percent Percent & No. Wight (g) aggregate (g) retained (getained coarser finer than Sieve + than (%) 6.83 28.24 1067 1660 2100 1990 1085 421 Total weight= 287 900 6.83 21.41 93.17 71.76 3/8" #4 #8 Pan 780 760 750 760 720 350 1230 365 71 29.26 8.68 1.69 89.63 98.31 100 10.37 1.69 0.00Explanation / Answer
Prob.1
There are four conditions:
(1) Dry aggregates : Having zero water content, and whole weight is equal to the weight of the solid particles of the aggregates.
(2) Partially saturated : Voids are partially filled, so the weight is comprised of the water and solids.
(3) Saturated Surface Dry(SSD): Whole of the voids are filled with water and weight is comprised of the solids and water insides the pores of solid structes, but no water on the outside surface of aggregate. Here water content is known as the absorption capacity of the aggregates.
(4) Saturated: In this case the water may be present on the surface. The total weight exceeds the SSD aggregates.
Q.2.
water conetent = 10%, so weight of water = 0.1*100 = 10 lbs.
Over dry weight will carry only solid weight, so weight = 100-10 = 90 lbs.
Absorption capacity is 4%, so out of 10%, 6% is on the surface, so its weight = 0.6*10 = 6 lbs.