A parallel-plate capacitor is charged toan electric potential of 327 V by moving

Question

A parallel-plate capacitor is charged toan electric potential of 327 V by moving 4.00E+16 electrons fromone plate to the other. How much work is done in charging thecapacitor?

V = 327 V
# of e- = 4.00e16 electrons
W = ?
V = -W/q0 => W =(-V)/q0
q0 = 4.00e16 electrons (-1.60e-19 C / 1electron) =-6.40e-3 C
W = (-327 V)(-6.40e-3 C)
     = 5.11e4 J

But this was incorrect. I tried -5.11e4 J too and that was alsoincorrect. Am I not allowed to use this equation for this type ofproblem? Because I don't know what other formula there is thatincorporates work and charge. Will rate lifesaver! Thanks!

Explanation / Answer

Potential V = 327 V Charge of 4 * 10 ^ 16 electrons q = 4 * 10 ^ 16 * 1.6 *10 ^ -19 C                                                      =6.4* 10 ^ -3 C work done for parallel palte capacitor W = V q                                                               = 2092.8 * 10 ^ -3 J                                                              = 2.0928 J

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