I have done this on my own, but i need some clarificationbefore i hand it in to the professor. Your help isappreciated. I need to model this situation... A person standing to the right exerts a 620 N force on a 70 kgblock at a 40 degree angle above the horizontal. The coefficient offriction is (0.5, 0.4) I have done this on my own, but i need some clarificationbefore i hand it in to the professor. Your help isappreciated. I need to model this situation... A person standing to the right exerts a 620 N force on a 70 kgblock at a 40 degree angle above the horizontal. The coefficient offriction is (0.5, 0.4)
Explanation / Answer
Given Force F = 620 N mass of the block m = 70 kg angle = 40 deg The coefficient of friction =? F = mg cos = F sin / mg cos = 620 sin 40/ 70 x 9.8 x cos 40 = 0.75