If, in 1/ = Ry (1/n1^2 1/n2^2) , you set n1 = 1 andtake n2 greater than 1 , you

Question

If, in 1/ = Ry (1/n1^2 1/n2^2) , you set n1 = 1 andtake n2 greater than 1 , you generate what is known as the Lymanseries.
a. Find the wavelength of the first member of this series. Thevalue of ¯h is1.05457 × 1034 J · s ; theRydberg constant for hydrogen is 1.09735 × 107 m1 ;the Bohr radius is 5.29177 × 1011 m; and the groundstate energy for hydrogen is 13.6057 eV. Answer in units of nm.
b.Consider the next three members of this series. The wavelengthsof successive members of the Lyman series approach a common limitas n2 -> . What is this limit? Answer in units of nm.

Explanation / Answer

given that 1/ = R(1/nf2 -1/ni2) in the liman series = nf = 1 and ni =234 . ........ when nf = 1 amd ni = 2 gives firstmember 1/ = 1.097 * 107 m-1 (1/12 - 1/22) = 0.822 * 107 = 121* 10-9m = 121nm next when ni = 3 then 1/ = 1.097 * 107m-1 ( 1/12 - 1/32) = 0.97 *107 = 102nm when ni = 4 then 1/ = 1.097 * 107 m-1 (1/12 - 1/42) = 1.02 * 107 = 97nm when ni = then 1/ = 1.097 * 107 m-1 (1/12 - 1/) = 91nm so 91nm is limit of lyman series. = 97nm when ni = then 1/ = 1.097 * 107 m-1 (1/12 - 1/) = 91nm so 91nm is limit of lyman series.

Related Questions

Navigate

• Browse (All)
• Browse I
• Subjects

---