A 36.5 kg box initially atrest is pushed 5.35 m alonga rough, horizontal floor w

Question

A 36.5 kg box initially atrest is pushed 5.35 m alonga rough, horizontal floor with a constant applied horizontal forceof 130 N. If the coefficientof friction between box and floor is 0.300, find the following. (a) the work done by the applied force
J

(b) the increase in internal energy in the box-floor system due tofriction
J

(c) the work done by the normal force
J

(d) the work done by the gravitational force
J

(e) the change in kinetic energy of the box
J

(f) the final speed of the box
m/s (a) the work done by the applied force
J

(b) the increase in internal energy in the box-floor system due tofriction
J

(c) the work done by the normal force
J

(d) the work done by the gravitational force
J

(e) the change in kinetic energy of the box
J

(f) the final speed of the box
m/s

Explanation / Answer

(a) thework done by the applied force
F*d = 695.5 J

(b) the increase in internal energy in the box-floor system due tofriction
mgd = 574.1 J

(c) the work done by the normal force
N*d*cos(90) = 0

(d) the work done by the gravitational force
mg*d*cos(90) = 0

(e) the change in kinetic energy of the box
695.5 - 574.1 = 121.4 J

(f) the final speed of the box
121.4 = mv2/2, so v = 2.58 m/s

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