Greetings, The question asks \"how high is the ball above or below thehand when

Question

Greetings, The question asks "how high is the ball above or below thehand when it hits the wall? Explain." I used the equation: Vy = Vyo - gt and got(-9.8m/s)(0.5s) = -4.9m
The problem is as follows: A woman hits a rubber ball with herhand and gives it an initial velocityof 20m/s, 10 deg abovehorizontal. The ball hits a wall 10m away from the woman'shand. Greetings, The question asks "how high is the ball above or below thehand when it hits the wall? Explain." I used the equation: Vy = Vyo - gt and got(-9.8m/s)(0.5s) = -4.9m
The problem is as follows: A woman hits a rubber ball with herhand and gives it an initial velocityof 20m/s, 10 deg abovehorizontal. The ball hits a wall 10m away from the woman'shand.

Explanation / Answer

The initial velocity of the rubber is u = 20 m/s The angle made by the rubber ball is = 10oabove the horizontal The ball hits a wall 10m away from the woman's hand. The height of the rubber ball when it hits the wall is H = (u2 * sin2/2g) or H = ((20)2 * sin2(10o)/(2* 9.8)) or H = 0.61 m Therefore,the rubber ball is 0.61 m above the hand when ithits the wall.

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