I have no idea how to solve for A or B. Any help is GREATLYappreciated! :0) In a

Question

I have no idea how to solve for A or B. Any help is GREATLYappreciated! :0) In a free body diagram of two weights on a pulley system,object m1= 9.0 kg and object m2= 3.5 kg. Thecoefficient of static friction between m1 and thehorizontal surface is 0.50 while the coefficient of kineticfriction is 0.30. A) If the system is released from rest, what will itsacceleration be? (answer in m/s2) B) If the system is set in motion with m2 movingdownward, what will be the acceleration of the system? (answer inm/s2) I have no idea how to solve for A or B. Any help is GREATLYappreciated! :0) In a free body diagram of two weights on a pulley system,object m1= 9.0 kg and object m2= 3.5 kg. Thecoefficient of static friction between m1 and thehorizontal surface is 0.50 while the coefficient of kineticfriction is 0.30. A) If the system is released from rest, what will itsacceleration be? (answer in m/s2) B) If the system is set in motion with m2 movingdownward, what will be the acceleration of the system? (answer inm/s2)

Explanation / Answer

first thing you need to do is to find your forces. Fnet = F1+ F2 = (mass of the system) acceleration. F1 is thefrictional force between M1 and the surface. this force isnegative meaning it is opposite of F2 which is the force due togravity working on M2. When the system is at rest we use thestatic friction coefficient to determine the frictional force, andwhen the system is in motion we use the kineticcoefficient. A.) F1 = -M1*g*(0.5), F2 = M2*g, Fnet = (M2*g) - (M1*g*(0.5))= (M1 + M2)*a, so a = (g(M2 - (M1*(0.5))))/(M1 + M2) B.) Same process just plug in the kinetic coefficient rather thanthe static

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