Hey guys, I\'m stuck with this question, I went through the book but doesn\'t ex

Question

Hey guys, I'm stuck with this question, I went through the book but doesn't explain much.
here is the question: A hammer taps on the end ofa 4.00-m-long metal bar at room teperature. a microphone at theother end of the bar picks up two pulses of sound, one that travelsthrough the metal and one that travels through the air. the pulsesare separated in time by 11. 0 ms. what is the speed of the soundin this metal?
Rating will be provide
thanks Hey guys, I'm stuck with this question, I went through the book but doesn't explain much.

Rating will be provide
thanks

Explanation / Answer

           Given that the length of the bar is L = 4.00 m            The time difference between the two pulses is t = 11.0 ms =11.0*10-3s            Let the velocity of the sound at room temparature is V1 = 343m/s -------------------------------------------------------------------------------------             time taken to travelle the distance L by the sound is t1= L / V1                                        timetaken to travelle the distance L by the sound in rod is t2 = L / V2                  butfrom the given data t = t2 - t1=  11.0*10-3s                                                            (L /V2 - L/V1) = 11.0*10-3s                                                                (1/V2-1 /V1) =11.0*10-3s /L                                                                       1/V2=1 /V1 + 11.0*10-3s /L                                                                    V2= 1 / ( 1 /V1 +11.0*10-3s /L )                                                                         = ---------- m/s          

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