In 1990 Walter Arfeuille of Belgium lifted a 281.5 kg objectthrough a distance o
ID: 1738730 • Letter: I
Question
In 1990 Walter Arfeuille of Belgium lifted a 281.5 kg objectthrough a distance of 17.1 cm using only his teeth. a. How much work did Arfeuille do on the object? b. What magnitude force did he exert on the objectduring the lift, assuming the force is constant. I found a. by F = ma = 281.5kg * 9.8 = 2758.7 N. and then W =Nm = 2758.7N * 0.171 m = 471.7377 J. But I don't know how tofind b. and it isn't the same as the first part of a. In 1990 Walter Arfeuille of Belgium lifted a 281.5 kg objectthrough a distance of 17.1 cm using only his teeth. a. How much work did Arfeuille do on the object? b. What magnitude force did he exert on the objectduring the lift, assuming the force is constant. I found a. by F = ma = 281.5kg * 9.8 = 2758.7 N. and then W =Nm = 2758.7N * 0.171 m = 471.7377 J. But I don't know how tofind b. and it isn't the same as the first part of a.Explanation / Answer
for part b, you just take the mass of 281.5 kg, times the acceleration to due gravity, 9.8...which gives you 2758.7 N. And if you're question is asking for kN (kiloNewtons), then you just divide that by 1000 to give you 2.7587