The coefficient offriction between the 3.00 kg block and surface in the figure b

Question

The coefficient offriction between the 3.00 kg block and surface in the figure belowis 0.300. The system starts from rest.What is the speed of the 5.00 kg ball when it has fallen1.70 m?
1 m/s The coefficient offriction between the 3.00 kg block and surface in the figure belowis 0.300. The system starts from rest.What is the speed of the 5.00 kg ball when it has fallen1.70 m?
1 m/s The coefficient offriction between the 3.00 kg block and surface in the figure belowis 0.300. The system starts from rest.What is the speed of the 5.00 kg ball when it has fallen1.70 m?
1 m/s The coefficient offriction between the 3.00 kg block and surface in the figure belowis 0.300. The system starts from rest.What is the speed of the 5.00 kg ball when it has fallen1.70 m?
1 m/s

Explanation / Answer

Let the required velocity of the 5kg block be v. At the same time velocity of the smaller block will bev. Frictional force acting between block and surface will be (Fr)= umg in backward direction. Consider 3kg block tied to 5 kg block as asystem. Initial Energy - Final Energy = workdone against friction by 3kg block Initail energy - Final energy = potential energy lostby 5kg block - kinetic energy gained by 3kg &5kg block Workdone against friction = (Fr)(d) Equating, (5 kg)(9.8 m/s2)(1.7m) - (1/2)(3kg +5kg)(v2) = (0.3)(3 kg)(9.8 m/s2)(1.7m) v = 4.13 m/s

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