a piece of aluminum has a volume of 1.4X10^-3 m^3 the coefficient of volume expansion for aluminum is69X10^-6 The temp of this object is raised from 20 to 320 Celcius. Howmuch work is done by the expanding aluminum if the air pressure is1.01X10^5 Pa ? Thank You for the help a piece of aluminum has a volume of 1.4X10^-3 m^3 the coefficient of volume expansion for aluminum is69X10^-6 The temp of this object is raised from 20 to 320 Celcius. Howmuch work is done by the expanding aluminum if the air pressure is1.01X10^5 Pa ? Thank You for the help
Explanation / Answer
Initial volume V = 1.4X10^-3 m^3 the coefficient of volume expansion for aluminum = 69X10^-6 temperature difference dt = 320 - 20 = 300 degreeC P = pressure 1.01X10^5 Pa change in volume d V = V dt = 28.98 * 10 ^ -6 m ^ 3 So, work done W = P * dV = 2.92698 J