Two capacitors, C 1 = 5.00 µF and C 2 =14.0 µF, are connected inparallel and the

Question

Two capacitors, C1 = 5.00 µF and C2 =14.0 µF, are connected inparallel and the resulting combination is connected to a 9.00 Vbattery. (a) What is the equivalent capacitance of thecombination?
1 µF

(b) What is the potential difference across each capacitor?
C1 = 2 V
C2 = 3 V

(c) What is the charge stored on each capacitor?
C1 = 4µC
C2 = 5µC (a) What is the equivalent capacitance of thecombination?
1 µF

(b) What is the potential difference across each capacitor?
C1 = 2 V
C2 = 3 V

(c) What is the charge stored on each capacitor?
C1 = 4µC
C2 = 5µC

Explanation / Answer

(a). the equivalent capacitance of the combination is C= C1+ C2                                                                                   = 19 F (b). Potential difference across C1 capacitor = 9V Potential difference across C2 capacitor =9V (c). Charge stored on C1 capacitor Q 1 = C1 * V                                                              = 45 C Charge stored on C2 capacitor Q 2 = C2 * V                                                        = 126 C

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