Consider a skateboarder who starts from rest at the top of a12.5 m-long ramp that is inclined at an angle of 15.0 degrees tothe horizontal. Assuming that the skateboarder's acceleration is gsin 15.0 degrees, find his speed when he reaches the bottom of theramp in 3.00 s. Thanks! Consider a skateboarder who starts from rest at the top of a12.5 m-long ramp that is inclined at an angle of 15.0 degrees tothe horizontal. Assuming that the skateboarder's acceleration is gsin 15.0 degrees, find his speed when he reaches the bottom of theramp in 3.00 s. Thanks!
Explanation / Answer
Given that the length fo the ramp is L = 12.5 m The angle of inclination is = 15.00 The accelaration is a = g sin15.00 Timetaken is t = 3.00s -------------------------------------------------------------------------- From the equationof motion the final velocity is V = U + at =0 + at = ( gsin15.00)(t) =( 9.8m/s2*sin15.00)(3.00s) =---------- m/s The accelaration is a = g sin15.00 Timetaken is t = 3.00s -------------------------------------------------------------------------- From the equationof motion the final velocity is V = U + at =0 + at = ( gsin15.00)(t) =( 9.8m/s2*sin15.00)(3.00s) =---------- m/s