After the spheresare connected, they have equal charges. So, you can tell the ne
ID: 1752390 • Letter: A
Question
After the spheresare connected, they have equal charges. So, you can tell the netcharge after the connection is made. Is it different before theconnection is made? Before: They attract each other. So, before, dothey have the same or opposite signs? Two identical conducting spheres, fixed in place, attract eachother with a force of 0.100 N when their center to centerseparation is 58.00 cm. The spheres are then connected by a thinconducting wire. When the wire is removed, the spheres have a netpositive charge and repel each other with an electrostatic force of0.044 N. What was the initial negative charge on one of thespheres, and what was the initial positive charge on theother?(Hint: Use charge conservation and solve for one of theinitial charges. You will end up with a quadratic equation. Thesolutions give you the positive and negative charges.) Initial negative charge 1 C. Initial positive charge 2 C. After the spheresare connected, they have equal charges. So, you can tell the netcharge after the connection is made. Is it different before theconnection is made? Before: They attract each other. So, before, dothey have the same or opposite signs?Explanation / Answer
F = .100 N r = .58 m F = kqQ/r^2 qQ=Fr^2/k F' = .044 N F ' = k(Q - q)2/(4r2) so Q - q = 2r (F '/k) (Q + q)2 = (Q - q)2 + 4qQ =(2r)2(F' + F)/k so Q + q = 2r [(F + F')/k] so Q = r [(F + F') + F']/k =3.6*10-6 C q = r [(F + F') - F']/k = 1.04*10-6C answers: a: -1.04e-6 C b. 3.6e-6 C Note: i noticed you typed your answer in as -1.00e-5 and3.00e10-6...the first one is just off by the power...and on thesecond..you should type your answer in as e-6 not e10-6