I have two of them. I\'m thinking that they are pretty similar,unfortunately I c

Question

I have two of them. I'm thinking that they are pretty similar,unfortunately I can't figure out either.
1.) A 0.50-kg block attached to and ideal spring with a springconstant of 80N/m oscillates on a horizontal frictionless surface.The total mechanical energy is 0.12 J. The greatest speed of theblock is:
0.15 m/s 0.24 m/s 0.49 m/s 0.69 m/s 1.46 m/s
2.) A 0.50-kg block attached to and ideal spring with a springconstant of 80 N/m oscillates on a horizontal frictionless surface.When the spring is 4.0 cm longer than it's equilibrium length, thespeed of the block is 0.50 m/s. The greatest speed of the blockis: 0.23 m/s 0.32 m/s 0.55 m/s 0.71 m/s 0.93 m/s
1.) A 0.50-kg block attached to and ideal spring with a springconstant of 80N/m oscillates on a horizontal frictionless surface.The total mechanical energy is 0.12 J. The greatest speed of theblock is:
0.15 m/s 0.24 m/s 0.49 m/s 0.69 m/s 1.46 m/s
2.) A 0.50-kg block attached to and ideal spring with a springconstant of 80 N/m oscillates on a horizontal frictionless surface.When the spring is 4.0 cm longer than it's equilibrium length, thespeed of the block is 0.50 m/s. The greatest speed of the blockis: 0.23 m/s 0.32 m/s 0.55 m/s 0.71 m/s 0.93 m/s

Explanation / Answer

Question 1) when the block is moving at its max speed, all of the potentialenergy will be kinetic energy: KE=.5*mv2.12=.5*.5*v2 v=.693 m/s Question 2) the total energy is going to be the sum of the kinetic energy andthe potential energy E=.5*(kx2+mv2) E=.5*(80*.042+.5*.52) E=.1265 J KE=.5*mv2 .1265=.5*.5*v2 v=.711 m/s

Related Questions

Navigate

• Browse (All)
• Browse I
• Subjects

---