Assuming equal rates of deceleration, how much further wouldyou travel if braking from 61mi/h to rest that from 32 mi/h. A bicyclist starts a timed race at 6 mi/h. In order to win, hemust average 21 mi/h. Assuming constant acceleration from thestart, how fast must he be traveling at the end of the race? Assuming equal rates of deceleration, how much further wouldyou travel if braking from 61mi/h to rest that from 32 mi/h. A bicyclist starts a timed race at 6 mi/h. In order to win, hemust average 21 mi/h. Assuming constant acceleration from thestart, how fast must he be traveling at the end of the race?
Explanation / Answer
Distance traveled is x = v2/2a extra distance traveled is [(61mi/h)2 -(32mi/h)2]/2a =(1348.5mi2/h2)/a Suppose distance to be traveled is x then time taken for the travel is x/(21mi/h) now if he starts at 6mi/h and aceelerates then the speed ofthe bicyclist at the end of the race is vf= 6mi/h + a[x/(21mi/h)]