A dipole of moment 0.3 e· nm is placed in a uniform electric field with a magnit

Question

A dipole of moment 0.3 e· nm is placed in
a uniform electric field with a magnitude of
20000 N/C.

What is the magnitude ofthe torque on the
dipole when the dipole is perpendicular to the
electric field? Answer in units of N · m.

What is the magnitude ofthe torque on the
dipole when the dipole makes an angle of 60?
with the electric field?

Find the potential energy of the dipole in the
electric field at 60? . Answer in units of J.

I tried to solve it using -pEsin(theta)..and -pEcos(theta)
but had no luck, the answer was wrong..HELP. please

Explanation / Answer

The formula for the torque is                    = Ep sin                     = (20000N/C)(0.3(1.6*10-19C)*(10-9m))sin90o the magnitude of the torque on the dipole when thedipole makes an angle of 60 with the electric field is                  = Ep sin               =(20000N/C)(0.3(1.6*10-19C)*(10-9m))sin60o Simplifying we get the answer. the magnitude of the torque on the dipole when thedipole makes an angle of 60 with the electric field is                  = Ep sin               =(20000N/C)(0.3(1.6*10-19C)*(10-9m))sin60o Simplifying we get the answer. Simplifying we get the answer.

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