a 150N sled is pulled up a 28 degree slope at constant speedby a 100N force that

Question

a 150N sled is pulled up a 28 degree slope at constant speedby a 100N force that is parallel to the slope a. what is the coefficient of kinetic friction between thesled and the slope? b. the sled is then released when near the top of the hill.what is the acceleration of the sled as it slides down thehill? please show all work a 150N sled is pulled up a 28 degree slope at constant speedby a 100N force that is parallel to the slope a. what is the coefficient of kinetic friction between thesled and the slope? b. the sled is then released when near the top of the hill.what is the acceleration of the sled as it slides down thehill? please show all work

Explanation / Answer

a) The coefficient of the kinetic friction be k,we have:           100N -mgsin(28) - mgcos(28)k = 0         =>k = [100N-mgsin(28)]/mgcos(28)
   =[100N-150N*sin(28)]/(150N*cos(28))
                = 0.223

b) let the acceleration be a, we have:           mgsin(28) - mg cos(28)k = ma            a= gsin(28) - gcos(28)k
             = 2.67m/s2

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---