Imagine that researchers obtained five mutations (1 to 5), each one responsible
ID: 176295 • Letter: I
Question
Imagine that researchers obtained five mutations (1 to 5), each one responsible for inability of frogs to croak. Pairwise crosses of the true-breeding non-croaker parents of each type sometimes produced croaker progeny, and sometimes not, as shown below It was concluded that the 'croaker phenotype involves three different genes with mutations grouped as follows: (1.4) (2, 3) (5) five different genes, each mutation in a separate gene: (1) (2) (3) (4) (5) four different genes with mutations grouped as follows: (1) (2.3) (4) (5) three different genes with mutations grouped as follows: (1) (2.3) (4, 5) four different genes with mutations grouped as follows: (1.2) (3) (4) (5)Explanation / Answer
The table is given for complementation test. Which reveals the mutation in recessive genes, in such mutation both alleles have to be present so the minus marked progeny from cross will have mutations in recessive genes.
On the basis of that we can find the pair of genes which are responsible for that. So the best option is to choose is B, because the same gene pair is also a cause of mutations.