Please check that I did question # 1 correctly and HELP me with #2. I am not sur
ID: 176954 • Letter: P
Question
Please check that I did question # 1 correctly and HELP me with #2. I am not sure how to work that out on my calculator...
1) The Yeast genome sequencing project finished in 1996. The complete genome contains 1.2 x 107 base
pairs.
a) If 3.6 X 107 base pairs of sequence were generated as part of the project, what fold coverage was
obtained? 1.2E7 * 3 = 3.6E7. Thus we have 3X coverage
b) With this fold coverage, what is the probability that any particular base was not sequenced?
e^-3 = 0.0497 --> 0.050% no sequenced?
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2)
1.83 million bases =genome size
sequence 1.83 million, 1X coverage]
what is P0 ?
Explanation / Answer
1. a) The fold coverage is calculated as: C = LN/G, where C = fold coverage, L = read length, G = haploid genome length, and N = number of reads.
Fold coverage of this given genome = 3.6 x 107 / 1.2 x 107 = 3.
b) P0 = e-c = e-3 = 0.05, i.e., 5% is not sequenced, 95% is sequenced.
2. c = 1, therefore, P0 =e-1 = 0.37. 37% is not sequenced, only 63% is sequenced.