Please check that answers that are written and help answer the remaining questio

Question

Please check that answers that are written and help answer the remaining questions! Thank you!

D Week 1 3 x . D Name x V m currents x Q Mall AV X M can 20 x D 2018-03- x v D 201803. x e colleges x G suppose x G Home I c ( G cheggSt X 201803 × file: 778b48479b4e406f08dbb641 ce1 b9/ Downloads/201 8-03-21 %2011-12 pdf Bookmarks Netflixpython trainingNew folder Medical School XStream TV Other bookmarks 3. Coflege students, alcohol, and sleep Suppose that a simple random sample of 29 college-age men and women was randomly divided into two groups. The first group of ni-15 people was given ½ liter of red wine before going to sleep. The second group of n214 people was given no alcohol before going to sleep. Everyone in both groups went to sleep at 11.00pm. The average brain wave activiry (fron 4:00- was determined for each iedividual i Group 1 (n, 15 ) Avrroge brin wave activity from 4:006:00am: the groups. The results follow 16.0 19.6 19.9 20.9 20.3 . 1 16.4 206 20.1 22.3 8B 19.1 174 21.1 22.1 Group 2(ng14)Average brain wave activity from 4:00-6.0m 8.2 54 68 . 4.75.9 2.9 76 10.2 64 8.8 54 83 5 The mean for group one is a little over 13 puints higher than foe group two, but chat might not be the case for the popalation at large. Assaming the two groups are independent and that both groaps are normally distributed, use a hypothesis test with typificance level 0.10 to tesz the claim that the average brain wave for pxple of college age who are given 6 liter of red wine before going to sleep is at least 13 poines higher than the average brain wave for those who are not.[HINT: In your hypothesis and claim instead of comparing ph and 2 directly, you should compare (-13) with 2.You can do this by comparing 13) with ,by putting (-13) values into the in your calculator! ZTest) or ITTestl or (2-SampTestI or (2 (circle one) orS1. One-Sided Left One Sided RightTwo Sided circle one)? Test statistic: zor I. Critical Value(s) (based oa Graph (sketch): ): P value: Conclusions? (Circle one): Reject H Fail to Reject H Interpretation

Explanation / Answer

Two-Sample T-Test and CI: C1, C2

Two-sample T for C1 vs C2

     N   Mean StDev SE Mean
C1 15 19.65   1.86     0.48
C2 14   6.59   1.91     0.51

Difference = (C1) - (C2)
Estimate for difference: 13.061
90% lower bound for difference: 12.142
T-Test of difference = 13 (vs >): T-Value = 0.09 P-Value = 0.466 DF = 27
Both use Pooled StDev = 1.8828

TS = 0.09

P-Value = 0.466

we fail to reject the null

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