Inductors in series . Two inductors L 1 = 1.14 H and L 2 = 2.01 H are connected
ID: 1769638 • Letter: I
Question
Inductors in series. Two inductors L1 = 1.14 H and L2 = 2.01 H are connected in series and are separated by a large distance so that the magnetic field of one cannot affect the other. (a) Calculate the equivalent inductance. (Hint: Review the derivations for resistors in series and capacitors in series.Which is similar here?) (b) What is the generalization of (a) for N = 19 similar inductors L = 3.29 H in series?
(a) H Inductors in series. Two inductors L1 = 1.14 H and L2 = 2.01 H are connected in series and are separated by a large distance so that the magnetic field of one cannot affect the other. (a) Calculate the equivalent inductance. (Hint: Review the derivations for resistors in series and capacitors in series.Which is similar here?) (b) What is the generalization of (a) for N = 19 similar inductors L = 3.29 H in series? H HExplanation / Answer
(a) Voltage is proportional to inductance ) just as, for resistors, it is proportional to resistance. Since the (independent) voltages for series elements add (V1 + V2), then inductances in series must add,
Leq = L1+L2 = 1.14 +2.01 = 3.15 H
just as was the case for resistances.
Note that to ensure the independence of the voltage values, it is important that the inductors not be too close together . The requirement is that magnetic field lines from one inductor should not have significant presence in any other.
(b) generalisation is that 19 inductors of L=3.29 H are connected in series.
Leq = ?Nn=1 Ln
= 19*3.29 = 62.51 H