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Class Management 1 Help Homework 6 Begin Date: 11/12/2017 1201.00 AM-Due Date: 1

ID: 1770303 • Letter: C

Question

Class Management 1 Help Homework 6 Begin Date: 11/12/2017 1201.00 AM-Due Date: 11/19/2017 11 5900 PM Ead Date: 11/19/2017 11-5900 PM (4%) Problem 3: Suppose the ski patrol kwas a rescue sled carrying an impred skin, with a combined mass of 97.5 kg, down a 600° slope at constant speed, as shown in the Figure. The coefficient of kinctic friction between the sled and the snow is 0.100 Assignment States Click here for detailed view 60 Ctheexpertta.com 25% Part (a) How mach work, n 25% Part () d ne by firton astheded moes tend the r pdes, Problem States Crade Samary 1 Completed 2 Completed 3 Partial 4 Completed Potental 90% Atfempts remaining Partial atan0 acota sinho 6 Completed 7Completed 8 Completed 9 Completed 10 Completed 3% Degrees Radianso I give upt Feedback: deduct on per feedback F7 F8

Explanation / Answer

Here,

m = 97.5 Kg

theta = 60 degree

u = 0.100

part A)

frictional force , f = u * mg * cos(theta)

f = 0.10 * 97.5 * 9.8 * cos(60 degree)

f = 47.8 N

work done by friction = -47.8 * 32.5

work done by friction = - 1553 J

part B)

Now, for constant speed

tension in the cable , T = m *g * sin(theta) - friction

T = 97.5 * 9.8 * sin(60 degree) - 47.8

T = 780 N

work done by tension = -780 * 32.5

work done by tension = -25340 J

the work done by tension is -25340 J