Please show work for the answer 17. 13 points | Previous Answers Tipler6 6.P.060
ID: 1770691 • Letter: P
Question
Please show work for the answer
17. 13 points | Previous Answers Tipler6 6.P.060 My Notes Ask Your To complete your master's degree in physics, your advisor has you design a small, linear accelerator capable of emitting protons, each with a kinetic energy of 11.7 kev. (The mass of a single proton is 1.67 x 1027 kg.) In addition, 1.00 x 109 protons per second must reach the target at the end of the 1.60-m-long accelerator (a) What the average power must be delivered to the stream of protons? 1.87 (b) What force (assumed constant) must be applied to each proton? 1.00 1e(-15) × N (c) What speed does each proton attain just before it strikes the target, assuming the protons start from rest? m/s Use the definition of average power and the work-kinetic energy theorem to find the average power delivered to the target. A second application of the work-kinetic energy theorem and the use of the definition of work will yield the force exerted on each proton. Finally, use the definition of kinetic energy to find the speed of each proton just before it hits the target eBook Submit Answer Save ProgressPractice Another Versiorn My Notes Ask Your Teac 18. 99 points | Previous Answers Tipler6 6 P069Explanation / Answer
(A) KE = (1 x 10^9) (11.7 x 10^3 eV)
= (11.7 x 10^3 x 10^9 x 1.6 x 10^-19)
= 1.87 x 10^-6 J /s
So power = 1.87 x 10^-6 W
= 1.87 uW
(B) P = F v
v = d / t = (1.60)/1 = 1.6 m/s
(1.87 x 10^-6) = F (1.6)
F = 1.17 x 10^-6 N
(C) KE = m v^2 /2
11.7 x 10^3 x 1.6 x 10^-19 = (1.67 x 10^-27) v^2 /2
v = 1.50 x 10^6 m/s