An object moves in the +x-direction at a speed of 32 m/s . As it passes through

Question

An object moves in the +x-direction at a speed of 32 m/s . As it passes through the origin, it starts to experience a constant acceleration of 2.5 m/s2 in the -x-direction.

Part A

What will happen next?

What will happen next?

How much time elapses before the object returns to the origin?

What is the magnitude of the velocity of the object when it returns to the origin?

Part E

What is the direction of the velocity of the object when it returns to the origin?

What is the direction of the velocity of the object when it returns to the origin?

The object will keep traveling in the +x-direction. The object will travel in the +x-direction and then reverses its direction. The object will reverse its direction of travel at the origin.

Explanation / Answer

part A)

The object will travel in the +x-direction and then reverses its direction.

Xf = final position = 0

Xi = initial position = 0

Vi = initial velocity = 32 m/s

a = acceleration = - 2.5

using the equation

Xf = Xi + Vi t + (0.5) a t2

0 = 0 + 32 t + (0.5) (- 2.5) t2

t = 25.6 sec

Vf = final velocity

Vi = initial velocity = 32 m/s

t = 25.6 sec

a = acceleration = - 2.5

using the equation

Vf = Vi + at

Vf = 32 + (- 2.5) (25.6) = - 32 m/s

E)

-x-direction

Part B)

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