A rectangular coil of wire, 22.0 cm by 35.0cm and carrying a current of 1.95A, i
ID: 1773536 • Letter: A
Question
A rectangular coil of wire, 22.0 cm by 35.0cm and carrying a current of 1.95A, is oriented with the plane of its loop perpendicular to a uniform 1.50-T magnetic field (Figure 1) .
Part A
Calculate the net force that the magnetic field exerts on the coil.
Express your answer with the appropriate units.
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Part B
Calculate the torque that the magnetic field exerts on the coil.
Express your answer with the appropriate units.
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Part C
The coil is rotated through a 30.0angle about the axis shown, with the left side coming out of the plane of the figure and the right side going into the plane. Calculate the net force that the magnetic field now exerts on the coil. (Hint: In order to help visualize this three-dimensional problem, make a careful drawing of the coil when viewed along the rotation axis.)
Express your answer with the appropriate units.
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Part D
Calculate the torque that the magnetic field now exerts on the coil.
Express your answer with the appropriate units.
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Figure 1 of 1
A rectangular coil of wire, 22.0 cm by 35.0cm and carrying a current of 1.95A, is oriented with the plane of its loop perpendicular to a uniform 1.50-T magnetic field (Figure 1) .
Part A
Calculate the net force that the magnetic field exerts on the coil.
Express your answer with the appropriate units.
F=SubmitMy AnswersGive Up
Part B
Calculate the torque that the magnetic field exerts on the coil.
Express your answer with the appropriate units.
=SubmitMy AnswersGive Up
Part C
The coil is rotated through a 30.0angle about the axis shown, with the left side coming out of the plane of the figure and the right side going into the plane. Calculate the net force that the magnetic field now exerts on the coil. (Hint: In order to help visualize this three-dimensional problem, make a careful drawing of the coil when viewed along the rotation axis.)
Express your answer with the appropriate units.
F=SubmitMy AnswersGive Up
Part D
Calculate the torque that the magnetic field now exerts on the coil.
Express your answer with the appropriate units.
=SubmitMy AnswersGive Up
Provide FeedbackContinue
Figure 1 of 1
Axis 22.0 cm × . 35.0cmExplanation / Answer
a) As the current in the opposite sides of the rectangle is in opposite direction, and the force acting of the sides are also in opposite directions, so the net force on the coil will be 0.
b) As all the four forces are in the plane of coil, net torque due to them is 0.
c)The resultant of the four forces is still zero, Fnet = 0
d)The force on left and right sides are still parallel, their magnitudes are same, but the perpendicular distance between them is not zero, it is now
0.35sin30 = 0.175 m.
Magnitude of force on each side on left and right =BiL= 1.50*1.95*0.22
Hence the torque on the coil will be
1.50*1.95*0.22*0.175 = 0.113 Nm or 11.3*10^-2 Nm