Can someone please do D-F on this, i am very stuck. Thank you w) A constant curr
ID: 1775181 • Letter: C
Question
Can someone please do D-F on this, i am very stuck. Thank you
w) A constant current Iflows through a straight wire as shown above. A rectangular loop of wire with overall resistance R, length and width w is a distance x (to the close edge) from the straight wire. It is dragged to the right at a constant velocity v. The variable r refers to the distance from the wire to some vertical slice in the loop. Don't give up on (d) through (f) if you can't get the early parts! a) [3 pts] What is the magnetic field due to the straight wire B(r)? Draw an X or . b) [3 pts] Use an integral to determine the flux through the rectangular loop when it is c) [4 pts] Now let's consider what is happening as the loop moves. We can think of v as the inside the loop to indicate which direction the magnetic field points. a distance ax away from the wire. Hint: Think about what dA is for this case and ignore the velocity rate of change of x with respect to time (because it is!). Use this information to get the magnitude of the induced emf around the loop. Hint:-=-*-=-* u dt dx dtdr d) [3 pts] Use Lenz's Law to get the direction of current flow in the loop. Does it circulate clockwise or counterclockwise? Draw an arrow on the figure to show the direction of current flow e) [3 pts] Knowing the induced emf around the loop and the resistance R in the loop, what is the magnitude of the current flowing around the loop? Since the solution to (c) was kind of messy, just use for this part. [4 pts] In order to move the coil at constant speed, a force must be exerted to counteract the force due to the magnetic field. What force is required to move the loop at constant velocity? Hint: you only need to know the current in the loop and the magnetic field B(r). You may use your result from (e) for the current. f)Explanation / Answer
D. The straight current carrying wire produces a magnetic flux (inward flux) through the loop directed into the page. Using lenz's law we can say that, the magnetic field due to the induced current in the loop has to counteract the inward flux. So, if the inward flux is into the page, then flux due to induced current has to be out of the page. So the direction of current in the loop has to be counter clockwise.
E. The magnitude of induced current I = €/R , here € is induced emf.