Problem 7.24- Enhanced- with Feedback Part A The 1.0 kg block in the figure is t
ID: 1776039 • Letter: P
Question
Problem 7.24- Enhanced- with Feedback Part A The 1.0 kg block in the figure is tied to the wall with a rope. It sits on top of the 2.0 kg block. The lower block is pulled to the right with a tension force of 20 N. The coefficient of kinetic friction at both the lower and upper surfaces of the 2.0 kg block is -0370 Figure 1) What is the tension in the rope holding the 1.0 kg block to the wall? Express your answer with the appropriate units. You may want to review (D pages 169-172) alue Units Submit My Answers Give Up Part B What is the acceleration of the 2.0 kg block? Express your answer with the appropriate units. Figure 1-3 of 1 1kg 20 N alue Units 2 kg Submit My Answers Give UpExplanation / Answer
A)
Applying Newton’s 2nd law vertically to mass m1,
Fn1-m1g= ma=0
Fn1=m1g -----------(1)
Applying Newton’s 2nd law horizontally to mass m1,
Fnet=ma
-Ff = -T
T=Ff1
T=uk*Fn1
From (1),
T = uk*m1g
Plugging values,
T=0.370*1.0*9.81
T = 3.63 N
B)
Applying Newton’s 2nd law vertically to mass m1,
Fn2-(m1+m2)g= ma=0
Fn2= (m1+m2)g -----------(2)
Ff2 =uk*Fn2
From (2),
Fn2 = uk*(m1+m2)g
Plugging values,
Fn2=(1.0+2.0)*9.81 =29.43 ----------------(3)
Applying Newton’s 2nd law horizontally to mass m1,
Fnet=ma
F – Fn1 – Fn2 = m2*a
20 – 0.370*1.0*9.81 – 0.370*(1.0+2.0)*9.81.= 2.0*a
a= 2.15 m/s^2