Please answer the following question clearly. Ex 24.34 Part A A parallel-plate c

Question

Please answer the following question clearly.
Ex 24.34 Part A A parallel-plate capacitor has capacitance Co=7.50 pF when there is air between the plates. The separation between the plates is 1.10 | What is the maximum magnitude of charge that can be placed on each plate if the electric field in the region between the plates is not to exceed 3.00x10 V/m? Express your answer with the appropriate units. IQ-1 Value Units Submit My Answers Give Up Part B A dielectric with K- 3.00 is inserted between the plates of the capacitor, completely filling the volume between the plates. Now what is the maximum magnitude of charge on each plate if the electric field between the plates is not to exceed 3.00x101 V/m? Express your answer with the appropriate units. QValue Units Submit My Answers Give Up Provide FeedbackC

Explanation / Answer

Part A)-

Given is -

E = 3*104 V/m and C = 7.50pF and d =1.10 mm

We know that-

Emax =Vmax/d

3*104 = Vmax/(1.1 * 10-3)

Vmax = 33 volt

Now we also aware about -

Q = CV

Qmax = CVmax

Qmax = (7.50 * 10-12)(33)

Qmax = 247.5 10-12C

Part B)-

Now k= 3.00

Cnew = Cold . K = 7.50*3 pF

Cnew = 22.5 pF

Then-

Vmax will not be changed so-

Vmax = 33 volt

Then-

Q = CV

Qmax = CnewVmax

Qmax = (22.50 * 10-12)(33)

Qmax = 742.5 10-12C

Thank you !!! Have fun

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