Incorrect; Iry Again; 5 attempts remaining Problem 20.15 A helium ion (Q +2e) wh
ID: 1780181 • Letter: I
Question
Incorrect; Iry Again; 5 attempts remaining Problem 20.15 A helium ion (Q +2e) whose mass is 6.6x10 27 kg is accelerated by a voltage of 2100 V Part B What will be its radius of curvature if it moves in a plane perpendicular to a uniform 0.380 T field? Express your answer to two significant figures and include the appropriate units. Value Units Submit My Answers Give Up Part C What is its period of revolution? Express your answer to two significant figures and include the appropriate units. T-Vau UnitsExplanation / Answer
given helium ion
Q = 2e
mass m = 6.6*10^-27 kg
accelrating voltage V = 2100 V
B. B = 0.38 T
radius of curvature = r
then
mv^2/r = qvB
mv/r = qB
r = mv/qB
but
0.5mv^2 = qV
v = sqroot(2qV/m)
hence
r = sqroot(2Vm/q)/B
r = sqroot(2*2100*6.6*10^-27/2*1.6*10^-19)/0.38
r = 2.449 cm
C. period of revolution = T
v = 2*pi*r/T
T = 2*pi*r/sqroot(2qV/m) = 1.562*10^-5 s