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Incorrect; Iry Again; 5 attempts remaining Problem 20.15 A helium ion (Q +2e) wh

ID: 1780181 • Letter: I

Question

Incorrect; Iry Again; 5 attempts remaining Problem 20.15 A helium ion (Q +2e) whose mass is 6.6x10 27 kg is accelerated by a voltage of 2100 V Part B What will be its radius of curvature if it moves in a plane perpendicular to a uniform 0.380 T field? Express your answer to two significant figures and include the appropriate units. Value Units Submit My Answers Give Up Part C What is its period of revolution? Express your answer to two significant figures and include the appropriate units. T-Vau Units

Explanation / Answer

given helium ion

Q = 2e

mass m = 6.6*10^-27 kg

accelrating voltage V = 2100 V

B. B = 0.38 T

radius of curvature = r

then

mv^2/r = qvB

mv/r = qB

r = mv/qB

but

0.5mv^2 = qV

v = sqroot(2qV/m)

hence

r = sqroot(2Vm/q)/B

r = sqroot(2*2100*6.6*10^-27/2*1.6*10^-19)/0.38

r = 2.449 cm

C. period of revolution = T

v = 2*pi*r/T

T = 2*pi*r/sqroot(2qV/m) = 1.562*10^-5 s