I need help with the question. show work and details. Problem 28.46 In proton-be

Question

I need help with the question. show work and details.

Problem 28.46 In proton-beam therapy, a high-energy beam of protons is fired at a tumor. As the protons stop in the tumor, their kinetic energy breaks apart the tumor's DNA, thus killing the tumor cells. For one patient, it is desired to deposit 0.10 of proton energy in the tumor. To create the proton beam, protons are accelerated from rest through a 1.1×104 potential difference. Part A What is the total charge of the protons that must be fired at the tumor? Express your answer to two significant figures and include the appropriate units. - -9.09 . 10 6 C Submit My Answers Give Up Incorrect; Try Agaln; 2 attempts remalning

Explanation / Answer

Given energy is

E=0.1 Joules

potential difference

V+1.1*104 KV=1.1*107 volts

Total charge of protons thatmut be fired at the tumor is

Q=E/V=0.1/(1.1*107)

Q=9.09*10-9C

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