I need help with the questions that I got wrong. Thanks I e File Edit View Histo

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I need help with the questions that I got wrong. Thanks
I e File Edit View History Bookmarks People Window Help Secure https Do Homework Kimberly Pacheco /Awww.mathxl.com/Student/PlayerHo aspx?homeworkld 4102595928questionld 18flusheds false &old; 43260 38centerw Math 112: TTh 1-3 Kimberly Pacheco 2/11/17 1:18 PM Homework: Section 3.2 Homework Save Score: 0.27 of 1 pt 1 of 12 (12 complete) HW Score: 89.77%, 10.77 of 12 pts me 3.2.27 2011, the EQuestion Help crime rates mean rate of volent orime (per 100,000 people for 24 particular states was 413. The standard deviation was 167. Assume the distribution of violent is unimodal and symmetric. Complete parts (a) through (d)below. that The graph on the right is a of the distribution of the crime rates. What percentage of data should occur within two standard deviations of the mean? The percentage of data that occurs within two standard deviations of the mean should be 95%. Type a whole number) es How was the number 580, shown on the graph, obtained? O A. By taking 95% of the mean. Question is complete. Tap on the red indicators to see incorrect answers. All parts showing Similar Question

Explanation / Answer

1) The percentege of data between two standard deviations is 68% (1 on left + 1 on right)

for 95% (2 on left + 2 on right)

2) Given mean = 413, standard deviation = 167, N = 100000 for 24 states

values at 1 and 2 standard deviation distance on either side

at A,

p(X>x) = 0.975 or p(X<x) =0.025

- 1.96 = (X-413)/167

=85.88

=86

at B, p(X>x) = 0.84 or p(X<x)=0.16

Zvalue = -0.995

-0.995 = (X-413)/ 167

= 246.835

= 247

at C,

Z = 1.96

1.96 = (X-413)/167

X = 740.32

= 740

Between 86 and 740 we would expect 95% CI

Between 247 and 580 we would expect 68% CI

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