Please Answer 1. The graph in the figure shows the emf produced by a generator a
ID: 1783637 • Letter: P
Question
Please Answer
1. The graph in the figure shows the emf produced by a generator as a function of time t. The coil for the generator has an area of
A = 0.11 m2
and consists of
N = 50 turns.
The coil rotates in a field of magnitude 0.20 T.
Concepts:
(i) Can the period of the rotating coil be determined from the graph?
(ii) The emf produced by a generator depends on its angular frequency. How is the angular frequency of the coil related to its period? (Use the following as necessary: T. Do not substitute numerical values; use variables only.)
=
31.4
t = 0 s,
how much time is required for the generator to produce its peak emf? Express the answer in terms of the period T of the motion
(e.g., t = (0.1) T).
(Do not substitute numerical values; use variables only.)
t =
0.05
T, where T denotes the period of the coil motion.
V
(d) What is the emf when
t = 0.025 s?
V
Explanation / Answer
i) Yes
ii) = 2pi/T, T = Period
iii) Time taken for peak emf = T/4 = 0.25*T
iv) Two times
(a) Period = T = 0.04 s
(b) Angular frequency = = 2pi/T = 2pi/0.04 = 157.1 rad/s
(c) At t = T/4, Emf is maximum
(d) At t = 0.025 s, Emf will be half of maximum emf and negative.