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MasterinqPh,sics Chapter9- Google Chrome 0 i Serure | https://sessian.masteringnhysirs.cam/myctitemView?offset-nextassignmentProblemlD-86472102 Chapter 9Exercise 9.33 previous | 4 of 6 | next » Exercise 9.33 Part A A wagon wheel is constructed as shown in the figure Fiqure 1). The radius of the wheel is 0.300 m, and the rim has mass 1.41 kg . Each of the eight spokes, that lie along a diameter and are 0.300 m long, has mass 0.300 kg What is the moment of inertia of the wheel about an axis through its center and perpendicular to the plane of the wheel? kg m Submit My Answers Give Up Figure 1 | 011 rovide Feedback Continue 0.600 m Type here to search

Explanation / Answer

I = Moment of inertia of rim + 8 (moment of inertia of each spoke)

Irim = Mrim R2 = 1.41 (0.3)2 = 0.127 kgm2

Ispoke = Mspoke R2 /3 = (0.3) (0.3)2/3 = 0.03 kgm2

so

I = Moment of inertia of rim + 8 (moment of inertia of each spoke) = 0.127 + 8 (0.03) = 0.367 kgm2

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