If you were given 3 vectors (100i + 0j), (150cos(140)i + 150sin(140)j), (?cos(29
ID: 1785551 • Letter: I
Question
If you were given 3 vectors (100i + 0j), (150cos(140)i + 150sin(140)j), (?cos(290)i + ?sin(290)j)
What would the magnitude (?) have to be for this system to be in equilibrium?
Pulley 1 Pulley 2 Pulley 3 Angle 0 degrees 120 degrees Mass 50 g (0.050 kg) 120 g (0.100 kg) experimental 80g(0.080 kg) calculated By trial and error rotate the pulley with the 80 g mass around the force table until the system is in equilibrium (the string in the center). Draw a free body diagram of the system and calculate the angle needed to put the system in equilibriumExplanation / Answer
for the system t o be in equilibrium,
V1 + V2 + V3 = 0
=> 100i + 0j + 150cos(140)i + 150sin(140)j + ?cos(290)i + ?sin(290)j = 0
=> ? = -(100 + 150 cos140)/cos290 = 43.58
also ? = -150sin140/sin290 = 102.606
both values coming different, for no value of ?, the system can be in equilibrium