Please the solve the question below. Thank You. Question #5. (6 points) Initiall

Question

Please the solve the question below. Thank You.

Question #5. (6 points) Initially, in the circuit shown, the switch is open and the capacitors are discharged. The capacitance of C is 12 Farad (micro Farad 10", Farad) and the value of Cs is unknown. It is known that the equivalent capacitance of the two series capacitors is 4 uFarad. What is the value of the capacitor C? V-80 Volts 12 c) R= 0 31 M 6 1 point The resistor has a value of 0.31 M (mega -106 Ohm). The switch s is closed at ti later time, First, what is the total voltage across the two capacitors at the time when the charge on C, is 120 when the charge on capacitor C, is 120 uC, we want to determine the current in the circuit. ime t-o At some (QNote that you don't need to worry about the detailed time dependence of the charging of the capacitors.) I point What must be the voltage across the resistor at that time? V 1 point What is the current in the circuit at that time? What is the energy stored in C at that time? C. 2.57 1 point units ½ point I point - units ½ point

Explanation / Answer

C1 and C2 are in series,

C = C1 C2 / (C1 + C2)

4 (12 + C2) = 12 C2

C2 = 6 uF .......Ans

Q = 120 uC

Q = C V

V = 120 / 4 = 30 Volt ........Ans

Vr = 80 - 30 = 50 Volt .......Ans

I = Vr / R =50 / (0.31 x 10^6) = 1.613 x 10^-4 A ........Ans

U = Q^2 / 2 C1 = (120 x 10^-6)^2 / (2 x 12 x 10^-6)

U = 6 x 10^-4 J .........Ans

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