MasteringPhysics: Week 8 (graded) Google Chrome Secure https//session.masteringp

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MasteringPhysics: Week 8 (graded) Google Chrome Secure https//session.masteringphysics.com/myct/itemView?assignmentProblemID-83546030 Week & (graded Problem 10.03 * prevlous | 11 of 13 | next» Problem 10.03 Part A Three foroes are applied to a wheel of radius 0.350 m, as showm in the figure (Figure 1). One force is perpendicular to the rim, one is tangent to it, and the other one makes a 40.0 angle with the radius. Assume that F1 11.7N, F2 15.6N, and F3 8.50N What is the net torque on the wheel due to these three forces for an axis parpendicular to the wheel and passing through its center? Indicate the direction of the net torque by letting counterclockwise torques be positive. Express your answer in newton meters to three significant figures. Figure 1 Submit My Answers ive Up Continue 400 2:12 PM 10/26/2017 Search the web and Windows

Explanation / Answer

Torque due to Force = force x perpendicular distance between line of action and axis of rotation

Torque due to F1 = F1 x perpendicular distance between line of action and axis of rotation

= F1 x 0 ( as it passes through the centre of rotation)

= 0

Torque due to F2 = F2 x perpendicular distance between line of action and axis of rotation

= F2 x radius x sin 40

= 15.6 x 0.35 x sin 40

= 3.51 N.m ( clock wise)

Torque due to F3 = F3 x perpendicular distance between line of action and axis of rotation

= F3 x radius

= 8.5 x 0.35

= 2.975 N.m ( counter - clock wise)

Net Torque = Torque due to F1 + Torque due to F2 + Torque due to F3

= 0 - 3.51 + 2.975

= - 0.535 N.m

all the best in the course work

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