Problem 13: Three beads are placed on the vertices of an equilateral triangle of

Question

Problem 13: Three beads are placed on the vertices of an equilateral triangle of side d 1.8 cm. The first bead of mass m 110 g is placed on the top vertex The second bead of mass m2 = 65 g is placed on the left vertex. The third bead of mass m3 95 g is placed on the right vertex. ©theexpertta.com Part (a) Write a symbolic equation for the horizontal component of the center of mass relative to the left vertex of the triangle Expression 1 cim Select from the variables below to write your expression. Note that all variables may not be required. , , , a, d, g, h. J. k. m. m11. m2, m3. P. t Part (b) Find the horizontal component of the center of mass relative to the left vertex, in centimeters. Numeric : A numeric value is expected and not an expression. cm Part (c) Write a symbolic equation for the vertical component of the center of mass relative to the base of the triangle Expression Vcm Select from the variables below to write your expression. Note that all variables may not be required , , , a, d, g, h. j. k. m. m1, m2, m3, P. t Part (d) Find the vertical component of the center of mass relative to the base of the triangle, in centimcters. Numeric : A numeric value is expected and not an expression. cm

Explanation / Answer

m1 = 110 g

(x1 , y1) = (d/2 , d*sin60 ) = (0.9 , 1.55)

m2 = 65 g

(x2 , y2) = (0 , 0)

m3 = 95 g

(x3 , y3) = (d , 0) = (1.8 , 0)

part (a)

Xcm = ( (m1*x1) + (m2*x2) + (m3*x3) )/(m1+m2+m3)

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part (b)

Xcm = ( (110*0.9) + (65*0) + (95*1.8) )/(110 + 65 + 95)

Xcm = 1 cm

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part (c)

Ycm = ( (m1*y1) + (m2*y2) + (m3*y3) )/(m1+m2+m3)

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part (d)

Ycm = ( (110*1.55) + (65*0) + (95*0) )/(110 + 65 + 95)

Ycm = 0.63 cm

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