I kept getting wrong answer for c If the single slit is replaced with two slits
ID: 1790827 • Letter: I
Question
I kept getting wrong answer for c
If the single slit is replaced with two slits separated by a small distance d, the equation describing the location of the interference maxima looks almost the same as the equation used previously dsin = ma where m o, ±1, ±2,-3, In this equation, d is the dstance between the centers of the slits, is the angle from the center of the slits to the th maximum not minimum, as is used in the s ngle slit equation and is tne wavelength of the light The pattern for the double slit will contain features of both two-slit interference and single-slit diffraction. You must learn to recognize which features in the pattern result from two-slit interference and which result from single-slit diffraction. An experiment is set-up with a monochromatic light source, a double slit, and a screen, sar to what is shown on page 2 or the Interterence & Diffraction Lab. The experimenter measures and sketches the intensity pattern shown belaw -7 -6 -5 3 2 1 02 3 4 5 6 7 The scale along the bottom of the figure is in centimeters. What is the distance 2xj between the third maxima in the intensity pattern? Note: the central peak is the "zerath maximum", the two peaks closest to this on either side are the 'first maxima', the next two peaks are the 'second maxima", etc. (Units required, and you must be within 1 mm to be correct.) 2x,-3.7cm The slit to screen distance is D 2.200 m, and the slit separation is 0.219 mm. Use the formula for double-slit diffraction maxima and your value of 2x3 to find the light source's wavelength à. (Units required) 6.146.7 m If th light source's wavelength were set to 523 nm but everything else left the same, what would the distance between the second maxima 2x2 become? units required. when = 523 nm then 2x2-19 mrn Submit AnswerExplanation / Answer
d ( x/ L ) = m lamda
0.219 x 10^-3 ( x/ 2.2) = 2 (523 x 10^-9)
x( 0.099 ) = 2x 523 x 10^-6
x= 10.56 mm
2x= 21.13 mm apprx