Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

Please answer all! 12. Transcranial magnetic ) human brain. A sma COil is placed

ID: 1792482 • Letter: P

Question

Please answer all!

12. Transcranial magnetic ) human brain. A sma COil is placed on the changing magnetic field One such device generates Determine the perpendicular to the direction of the field . pulation (TMSis a noninvasive technique used to stimulate regions of the brief burst current rapidly Inside the brain. The induced enf Cat be sufficient to stimulate neuronal activity rates a magnetic field within the brain that rises from zero to 1.9 T in 100 ms . gnitude of the induced emt within a circle of tissue of radius 1.7 mm and that is A 0.912 n B. 0.835 mv o,643 mv D. 0.257 mv E.0.173 mv 13. An AC generator is to have a maximum output of 337 v. Each coil has an area 0.136 m and of a resistance of 15.1 N and rotates in a magnetic field of 0.698 T a frequency of 35Hz, with the axis with .2 of rotation perpendicular to the direction of the magnetic field. A. 45.1 A B. 38.2 A C. 22.3 A 18.5 A 10.4 A Suppose 14. Suppose the magnetic field in a given region of space is parallel to the Earth's surface, points north, and has a magnitude of 1.80x10 T. A metal cable attached to a space station stretches radially outwards 2.50 the potential difference km. Estimate that develops between the ends of the cable if it's traveling eastward around Earth at 7.70x10 m/s. A. 3510 v B. 3650 v C. 3890 V D. 3720 V E.3470 v oriented as shown. I 15. The bolt of lightning depicted in the figure below passes 200 m from a 115-turn col the current in the lightning bolt falls from 6.08x10 A to zero in 10.8 us, what is the average voltage induced in the coil? Assume the distance to the center of the coll determines the average magnetic field at s position. Treat the lightning bolt as a long, vertical wire. the coll' C. D. 152 A. 130 kV B. 128 kV 145 kVDkV E. 118 kV

Explanation / Answer

the induced emf is,

e = d/dt[BA]

= AdB/dt

= pi*r^2*dB/dt

= (3.14)(1.7x10-3)^2*[1.9/100x10-3]

= 0.173x10-3 V

= 0.173 mV

Option E is correct.