Problem 12 (5 pts): A resistor is connected to an AC power source with the rms v
ID: 1793725 • Letter: P
Question
Problem 12 (5 pts): A resistor is connected to an AC power source with the rms voltage (me) equal to 120 V. The resistor has a resistance = 100 . The power P dissipated in the resistor is oscillated between: A) 0 W and 144 W B) 0 W and 204 W C) 102 and 204 W D) 144 W and 288 W B) 0 W and 288 W Problem 13 (5 pts): A total of 8.0x 1013 protons pass a given point in a wire in 10s. What is the current in the wire? A) 0.21 HA B) 1.3 mA C) 3.2 HA D 1.3 HA 0 Problem 14 (5 pts): Two batteries and two resistors are connected together in the eircuit shown in the figure. What is the current of the circuit? 100 0.047 A B) 0.08 A C) 0.11 A D) 0.21 A B) None of the above 5 V 50Explanation / Answer
14) .
Let I be the current flowing clockwise through the circuit.
Apply kvl in the loop
100i + 12 + 50i = 5 volt
150i = -7 then I = -0.047 ampere
Negative sign indicates that current is flowing in anticlockwise direction.
Q.13) I = q/t then I = (8×10^13×1.6×10^-19)/(10)
I = 1.3 micro ampere
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