Please help me to solve the following question; Two gage marks are placed exactl
ID: 1815950 • Letter: P
Question
Please help me to solve the following question; Two gage marks are placed exactly 250 mm apart on a12-mm-diameter aluminium rod. Knowing that, with an axial load of6000 N acting on the rod, the distance between the gage marks is250.18 mm, determine the modulus of elasticity of the aluminiumused in the rod. I would really appreciate your help. Thanks in advance. Please help me to solve the following question; Two gage marks are placed exactly 250 mm apart on a12-mm-diameter aluminium rod. Knowing that, with an axial load of6000 N acting on the rod, the distance between the gage marks is250.18 mm, determine the modulus of elasticity of the aluminiumused in the rod. I would really appreciate your help. Thanks in advance.Explanation / Answer
The modulus of elasticity (E) is equal to the stress divided by thestrain. Stress = Force/Area Strain = change in length/initial length First, convert all your lengths into meters so your units match.250mm = 0.25m, 250.18mm = 0.25018m, and 12mm = 0.012m. Next, determine your stress by dividing the applied force (6000N)by the cross-section area which is determined by A = pi(r)^2. Stress = 6000N / pi(0.006m)^2 = 0.000113m^2 Next, determine the strain by dividing the change in length by theinitial length. Strain = 0.00018m/0.25m = 0.00072. Finally, divide your stress by your strain to determine the moduluswhich will have units in Pascals....your answer should be between50-150 GigaPascals - 1 GPa = 1 X 10^9 Pa.