Please help me to solve the problem below Solve Identification Problems (Note: A

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Please help me to solve the problem below

Solve Identification Problems (Note: An identification problem appears in each of the first six modules of this course. They can be used in any order) Identification of 14, 15, and 16 Scheme 11 shows the reaction of one equivalent of 14 (C12H26O2), which undergoes hydrolysis in acid catalyzed conditions to form one equivalent of 15 (C6H120) and 2 equivalents of 16 (C3HaO). Compound 14 is un-reactive with base and water. Compound 15 is chiral and has positive 2,4-dinitrophenylhydrazine and iodoform tests, but negative chromic acid and Tollens tests as illustrated in Scheme 12. Compound 16 is achiral and has a positive iodoform test as illustrated in Scheme 13. Provide a structures. Figures 4 and 5 are NMR spectra for 15 and 16. 1 H20 H30 L 15 (1 eq) L 16 (2 eq) 14 (1 eq) H20 OH No RXN Scheme 11

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