For the Full Wave Bridge Rectifier given , answer the following: a) What is the
ID: 1832360 • Letter: F
Question
For the Full Wave Bridge Rectifier given , answer the following:
a) What is the transformer secondary voltage Vrms?
(b) What is the transformer peak secondary voltage?
(c) If the capacitor is removed from the circuit, find the peak and average output voltage
Vpeak (out) = ________ V(out) AVG = ________
(d) If the capacitor is removed from the circuit, sketch the voltage waveform across RL.
(e) What is the PIV for each diode?
(f) Calculate the percent ripple (%r) at the rectifier output.
PLEASE ANSWER AS MUCH AS POSSIBLE! I WILL RATE LIFE SAVER AS ALWAYS
Explanation / Answer
a) Secondary voltage Vrms = 10V
b) Peak seconadary voltage Vm = Vrms 2 = (10)(1.414) = 14.14V
c) With the capacitor removed
Peak output voltage Vo(peak) = Vm = 14.14V
Average output voltage Vav = 0.636Vm = (0.636)(14.14) = 9V
d) Output waveform will be a pulsating as voltage fin one direction for both the input cycles
e) PIV = 2Vm = (2)914.14) = 28.28V
f) Percentage of ripple
AC ripple voltage at the output is Vo(rms) = 0.385Vm = (0.38(5)14.14) = 5.44V
% ripple = (Vo(rms) / Vav )100 = (5.44 / 9)100 = 60%