For the circuit below: R 1 = 5 ohms and R 4 is insignificantly small. If the bri
ID: 1835652 • Letter: F
Question
For the circuit below:
R1 = 5 ohms and R4 is insignificantly small.
If the bridge is not balanced, find the magnitude and the direction of the current flowing through R4.
The following is a step-by-step process to answer the above question.
2. Assume R4 is a short circuit. Compute the equivalent resistance from the terminal at the top of the bridge to the terminal at the bottom of the bridge.
ohms.
3. Find the current flowing from the source.
amperes.
4. Find the voltage across the parallel combination of R2 and R3.
volts.
5. Find the voltage across the parallel combination of R5 and R6.
volts.
6. Find the current flowing down through R2.
amperes.
7. Find the current flowing down through R5
amperes.
8. Now find the magnitude of the difference between the current flowing down through R2 and down through R5.
amperes.
9. Find the direction of the current flow through R4.
Explanation / Answer
1.The bridge is not balanced mate coz there needs 2 be a galvanometer in place of the R4 and other way 2 find is that here, R2/R3 is not equal to R5/R6. 2.Req=R1+((R2*R3)/R2+R3)+((R5*R6)/R5+R6) =5ohm+11.3191ohm+6.125ohm =22.4441ohm 3. current flowing =Vs/Req=Is=12.920A 4.resistance across R2 n R3 =11.3191ohm Voltage across it is (Is*11.3191O)=146.2539V 5.resistance across R5 n R6 =6.125ohm Voltage across it is (Is*6.125O)=79.135V 6.R2=19ohm; Voltage across R2 n R3 is 146.2539V Current through R2 =V/R2=7.69A 7.R5=49ohm; Voltage across R5 n R6 is 79.135V Current through R5 =V/R5=1.615A 8.Difference is 6.075A 9.Thus the Current flowing through R4 is 6.075A (or) 6A (left to right) ( negative in other direction or solve current through R3 n R6 and the difference will be the other)